If voltage doubles and resistance remains constant, how does current change?

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Multiple Choice

If voltage doubles and resistance remains constant, how does current change?

Explanation:
Current responds directly to voltage when resistance doesn’t change, as described by Ohm’s law I = V / R. If you double the voltage while keeping the resistance constant, the current must double because you’re pushing twice as much voltage across the same obstacle. For example, with V = 10 V and R = 5 Ω, I = 2 A; doubling the voltage to 20 V gives I = 4 A. So the current doubles. The other options don’t fit this relationship: halving, staying the same, or quadrupling would require different changes in voltage or resistance that aren’t present in this scenario.

Current responds directly to voltage when resistance doesn’t change, as described by Ohm’s law I = V / R. If you double the voltage while keeping the resistance constant, the current must double because you’re pushing twice as much voltage across the same obstacle. For example, with V = 10 V and R = 5 Ω, I = 2 A; doubling the voltage to 20 V gives I = 4 A. So the current doubles. The other options don’t fit this relationship: halving, staying the same, or quadrupling would require different changes in voltage or resistance that aren’t present in this scenario.

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